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CGP EDU Academic Team
Published on: August 14, 2026
CuCO 3 was strongly heated to obtain a residue A and gas B. The residue obtained was treated with a salt of sodium ‘X’ and oxide Y, which produced a blue colored glassy compound C on heating in oxidizing flame. The same combination of X and Y gave a green colored glassy compound D when Cr 2 (SO 4 ) 3 was heated with them in oxidizing flame. Match the following accordingly :
(a) | A | (P) | Cu(BO2)2 |
(b) | B | (Q) | Na2CO3 |
(c) | C | (R) | CuO |
(d) | X | (S) | CO |
(T) | Cu2O | ||
(U) | CO2 | ||
(V) | NaBO2 | ||
(W) | Cr(BO2)2 |
Text Solution
Verified by ExpertsThe correct answer is:
A
A → R, B → U, C → P, D → V
Sol. CuCO 3 
Cr 2 (SO 4 ) 3 
Green colored metaborate
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